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ZebY asked relay?problems connecting it?
Is relay the perfect thing for my situation?electronic problem? i have a 6V 4.5Ah Rechargeable Battery,And a small custom made 20W inverter hooked up with a CFL (compact Florescent lamp) and i also have an external charger 7.5V 1A with alligator clips at the end..i have a small switch on the wire going to the inverter(from battery) and i use it to turn it on..and when i want to charge it...i have to reconnect the alligator clips of the ext. charget all the time.. my BASIC question is...i WANT to make this system fully automatic..like..when the pow from the mains is comming..then it will trun off the lamp and charge the batt...when the power fails ..it turns on the lamp using the battery, NOTE:I DONT CARE for overcharging..i DONT need any over charging circuit..and i damn care if my battery explodes right in front of my eyes..I JUST NEED THE AUTOMATIC THING...please dont tell me circuit for charging and over charging cut-off.. now.. someone told me that i can use a thing called relay..exactly for this purpose...i got one rated at 12V..now..it has 5 Pins...2 are on one side..and 3 are on the other side...now that man told me that give it 12v frm mains via transformer...i thing my charger can be used for this purpose..it gives 7V and ..can it drive the 12V relay?..if so.. where to connect these things.. 2 pins are on left side..on the corners..and 3 pins are on the right side..2 of them are in corners..and 3rd in center..is slightly closer to the left pins..i found no pic..on the google.. NOTE: it is NOT a car Relay..it is a PCB mountable small pins relay what pins among them are the switches..?and where are the 12v voltage input pins to control the switch ? AND if i somehow found out the 2 pins of the coil inside it..how am i going to find polarity?.. what i have tried..i hooked up the 2 saperate pins(which i think are the coil pins) to 12v from my pc power supply..i DIDNT herd a click sound..nuthing..i tried with reversed polarity..still no sound...im really fucked up with this shit..thats y im posting this Q again!..with more details..PLEASE READ IT AND REPLY... what i have tried
And got the following answer:
Most relays like this operate on DC. The polarity doesn't normally matter. Yours is 12V but the charger is 7.5V (or less) when connected to the battery. It seems that is why it doesn't operate. A 12V relay may just operate on 9V or 10V but not 7.5V. You can easily find the connections with an ohm meter (multimeter). The coil will be a few hundred ohms. Just try all the combinations till you find the right pair. Seems likely it would be the two pins on one side. There are three pins for the relay contacts probably, so it seems to be a change over contact. An ohm meter will help you sort them out too, once you get it to operate. The contacts of your relay need to be rated at 1 Amp or more, to suit the maximum current drawn by the inverter. Connections. The relay operates whenever the power is on. Two of the three contacts are used. Use the ones that are open (not connected) when the power is on and the relay is operated, and closed when it is off. Connect these two contacts between the battery and the inverter, just like your switch. Use a separate supply to operate the relay. Use a 12V DC x 200 mA or greater plug pack. The relay contacts are connected in series with the battery and the inverter. They can be across the manual switch or not, as you want. You could use a 6V relay with a diode in series to adjust it to 6.7V. This could be operated by the charger, but you need another diode between the charger and battery to prevent the battery from holding the relay in when the power is off. It should be like 6 amps so it doesn't get hot. This diode may have an affect on the charge voltage. Simply go for the plug pack idea. You can probably find one around somewhere. If you have a 9V AC plugpack that would do, connect its output to a 1 Amp bridge rectifier AC terminals (often marked by a sine symbol), then the rectifier +/- to the relay. Connect a 16V/1000uF capacitor across the relay (plus to plus, minus to minus. This will produce around 12V DC. I edited this question a few hours later because I misread the question.